4w^2=1024

Solution for 4w^2=1024 equation:

4w^2=1024

We move all terms to the left:

4w^2-(1024)=0

a = 4; b = 0; c = -1024;
Δ = b2-4ac
Δ = 02-4·4·(-1024)
Δ = 16384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16384}=128$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-128}{2*4}=\frac{-128}{8}
=-16
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+128}{2*4}=\frac{128}{8}
=16
$